y^2+3y+7=2

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Solution for y^2+3y+7=2 equation:


Simplifying
y2 + 3y + 7 = 2

Reorder the terms:
7 + 3y + y2 = 2

Solving
7 + 3y + y2 = 2

Solving for variable 'y'.

Reorder the terms:
7 + -2 + 3y + y2 = 2 + -2

Combine like terms: 7 + -2 = 5
5 + 3y + y2 = 2 + -2

Combine like terms: 2 + -2 = 0
5 + 3y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 3y + -5 + y2 = 0 + -5

Reorder the terms:
5 + -5 + 3y + y2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 3y + y2 = 0 + -5
3y + y2 = 0 + -5

Combine like terms: 0 + -5 = -5
3y + y2 = -5

The y term is 3y.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3y + 2.25 + y2 = -5 + 2.25

Reorder the terms:
2.25 + 3y + y2 = -5 + 2.25

Combine like terms: -5 + 2.25 = -2.75
2.25 + 3y + y2 = -2.75

Factor a perfect square on the left side:
(y + 1.5)(y + 1.5) = -2.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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